Reputation: 349
I need to extract "/html/path" from strings like these:
generic/html/path/generic/generic/generic
I just need "path" and it's always coming after "html/". So it there a way to search for "html/" and get the string after it until a "/" is coming?
Upvotes: 0
Views: 161
Reputation: 37249
Another one to add to the mix:
In [1]: s = 'generic/html/path/generic/generic/generic'
In [2]: s.split('html/')[1].split('/')[0]
Out[2]: 'path'
Upvotes: 6
Reputation: 2234
You can use regex:
>>> regex = re.compile(".+html/(.+?)/")
>>> r = regex.search("generic/html/path/generic/generic/generic")
>>> r.groups()
(u'path',)
Python DOC: http://docs.python.org/3.3/library/re.html
Upvotes: 1
Reputation: 23312
This is just basic string manipulation
s="generic/html/path/generic/generic/generic"
i1= s.index("html/") + 5
i2= s.index("/", i1)
print s[i1:i2]
Upvotes: 1