CODEWITHSUNDEEP
regexscala
opensas
opensas

Reputation: 63415

scala: use a regular expression to escape certain characters

I'd like to escape certain characters preceding them with a \

I came up with the following solution:

scala> val l = List(".", "+", " ")
scala> val x = "hola.vamos a+escapar"
scala> l.foldRight(x){ (char, text) => text.replaceAll("""\""" + char, """\\""" + char) }
res1: java.lang.String = hola\.vamos\ a\+escapar

But I'm pretty sure there must be a way to use a regular expression to achieve it, but I don't know how to reference the matching text...

Upvotes: 1

Views: 272

Answers (1)

DaoWen
DaoWen

Reputation: 33019

"hola.vamos a+escapar".replaceAll("([.+ ])", "\\\\$1")

or

"hola.vamos a+escapar".replaceAll("([.+ ])", """\\$1""")

depending on if you prefer lots of quotes or lots of backslashes.

Upvotes: 4

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