Reputation: 1
I am generating a random.uniform(low=0.0, high=100.0, size=(150,150))
array.
I input this into a function that generates the X
, x
, and y
.
However, if the random test matrix is greater than 100, I get the error below.
I have tried playing around with theta values.
Has anyone had this problem? Is this a bug?
I am using python2.6 and scikit-learn-0.10. Should I try python3?
Any suggestions or comments are welcome.
Thank you.
gp.fit( XKrn, yKrn )
File "/usr/lib/python2.6/scikit_learn-0.10_git-py2.6-linux-x86_64.egg/sklearn/gaussian_process/gaussian_process.py", line 258, in fit
raise ValueError("X and y must have the same number of rows.")
ValueError: X and y must have the same number of rows.
Upvotes: 0
Views: 784
Reputation: 3336
My original post was deleted. Thanks, Flexo.
I had the same problem, and number of rows I was passing in was the same in my X and y.
In my case, the problem was in fact that I was passing in a number of features to fit against in my output. Gaussian processes fit to a single output feature.
The "number of rows" error was misleading, and stemmed from the fact that I wasn't using the package correctly. To fit multiple output features like this, you'll need a GP for each feature.
Upvotes: 0
Reputation: 40169
ValueError: X and y must have the same number of rows.
means that in your case XKrn.shape[0]
should be equal to yKrn.shape[0]
. You probably have an error in the code generating the dataset.
Here is a working example:
In [1]: from sklearn.gaussian_process import GaussianProcess
In [2]: import numpy as np
In [3]: X, y = np.random.randn(150, 10), np.random.randn(150)
In [4]: GaussianProcess().fit(X, y)
Out[4]:
GaussianProcess(beta0=None,
corr=<function squared_exponential at 0x10d42aaa0>, normalize=True,
nugget=array(2.220446049250313e-15), optimizer='fmin_cobyla',
random_start=1,
random_state=<mtrand.RandomState object at 0x10b4c8360>,
regr=<function constant at 0x10d42a488>, storage_mode='full',
theta0=array([[ 0.1]]), thetaL=None, thetaU=None, verbose=False)
Python 3 is not supported yet and the latest released version of scikit-learn is 0.12.1 at this time.
Upvotes: 3