CODEWITHSUNDEEP
javascriptclosures
hguser
hguser

Reputation: 36028

does this create a closure

I know this is the classic closure manner:

var dvs = document.getElementByTagName("div");

for (var i = 0, len = dvs.length; i < len; i++) {
    dvs.onclick = (function(i_) {
        return function() {
            alert(i_);
        };
    })(i);
}

However, in my application I am often confused, and my application is based on Google maps.

var app = function() {}
app.prototype = {
    init: function() {
        this.map = ..;
        this.infowindow = ..;
    },
    initEvent: function() {
        var that = this;
        google.maps.event.addListener(map, 'click', function() {
            that.infowindow.open(...);
        });
    }
}

Inner the initEvent method, I create a variable named that to refer to the context this, then call it in the callback function.

Does this create a closure?

I think so, because when the functionaddListener returns, the variable that is still referred, is closed.

Is this true?

Upvotes: 1

Views: 75

Answers (1)

jAndy
jAndy

Reputation: 235982

Technically spoken, every function in ECMAscript creates a closure when called. Its just the way lexical scope works. Without going into grand detail, the anonymous function which serves as event handler for the click event, closes over its parent contexts. One of those is the anonymous function which gets assigned to initEvent.

So, yes, the inner function creates a closure and therefore has access to that during its lifecycle.

Global Context <> initEvent <> click-event-handler

That is how the scope chain pretty much would look like.

Upvotes: 4

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