Reputation: 35
I have an array that looks like this:
array(3) {
[0]=>
array(2) {
[0]=>
string(10) "2012-11-14"
[1]=>
string(5) "3238"
}
[1]=>
array(2) {
[0]=>
string(10) "2012-11-13"
[1]=>
string(5) "3231"
}
[2]=>
array(2) {
[0]=>
string(10) "2012-11-13"
[1]=>
string(5) "3231"
}
I would like to write a foreach loop that would turn this array into:
array(2) {
[0]=>
array(1) {
"2012-11-14" => "3238"
}
[1]=>
array(1) {
"2012-11-13" => "3231"
}
So, basically, I would like to use the array element formatted as Y-M-D date as key to the second element in the array.
Upvotes: 1
Views: 90
Reputation: 3956
Given the following array...
$array = array(
0 => array(0 => "2012-11-14", 1 => "3238"),
1 => array(0 => "2012-11-13", 1 => "3231"),
2 => array(0 => "2012-11-13", 1 => "3231"),
);
putting it into a new array like this:
$new_array = array();
foreach ($array as $key => $item)
{
$new_array[$key][$item[0]] = $item[1];
}
print_r($new_array);
produces this output:
Array
(
[0] => Array
(
[2012-11-14] => 3238
)
[1] => Array
(
[2012-11-13] => 3231
)
[2] => Array
(
[2012-11-13] => 3231
)
)
My answer doesn't get rid of the duplicates, but the added dimension as specified in the original question means that duplicate dates as keys aren't an issue.
Upvotes: 2
Reputation: 36299
Here is what I came up with:
<?php
$original = array(
array(
"2012-11-14",
"3238"
),
array(
"2012-11-13",
"3231"
),
array(
"2012-11-13",
"3231"
)
);
$newArray = array();
foreach($original as $subArray){
$newArray[] = array($subArray[0] => $subArray[1]);
}
var_dump($newArray);
Upvotes: 0
Reputation: 2043
You can use this code to get what you want:
$dates = array(
array("2012-11-01", "3238"),
array("2012-11-03", "4321")
);
print_r($dates);
$result = array();
foreach($dates as $value) {
$result[][$value[0]] = $value[1];
}
print_r($result);
The output will look like the requested form:
Array
(
[0] => Array
(
[2012-11-01] => 3238
)
[1] => Array
(
[2012-11-03] => 4321
)
)
Codepad demo: http://codepad.org/XAmUEdYh
However, I would personally prefer Aykut's solution. You would of course have a problem when you've got two records with the same date, but the overall array layout is a bit nicer ;).
Upvotes: 0
Reputation: 36937
<?php
$newArray = array();
for($i=0;$i<count($arrayVariable);$i++)
{
$newArray[$arrayVariable[$i][0]] = $arrayVariable[$i][1];
}
echo '<pre>';print_r($newArray);echo '</pre>';
?>
Didn't test it but something like this should work in concept. Of course change arrayVariable
to your variable.. but that aside.
Upvotes: 0
Reputation: 3094
<?php
$data = array(
array("2012-11-14", "3238"),
array("2012-11-13", "3231"),
array("2012-11-13", "3231") // warning! when there are two record with same date, the second's count will be display
);
$result = array();
foreach ($data as $value) {
$result[$value[0]] = $value[1];
}
echo '<pre>';
print_r($result);
Upvotes: 2