CODEWITHSUNDEEP
regexlinuxbash
Satish
Satish

Reputation: 17467

How to cut base path using regex

Here is the example

SF_Library/example/Platform/Analyses-PLATFORM.part0.xml
SF_Library/example/Platform/Models-PLATFORM.part0.xml
SF_Library/example/Platform/Models-PLATFORM.car
SF_Library/example/Platform/DS-PLATFORM.car

I want to grab base path which is following. 

SF_Library/example/Platform/

Anybody know what regex should i use for it?

Upvotes: 0

Views: 3234

Answers (4)

Thomas
Thomas

Reputation: 182000

Alright, I'll indulge you.

^(.*/).*$

Dissection:

^     beginning of string
(     start of capture group
  .*  series of any number of any character
  /   a slash
)     end of capture group
.*    series of any number of characters that are not slashes
$     end of string

This works because * is greedy: it matches as many characters as it can (so it will include all the slashes right up to the last one).

But as the other answers have pointed out, a regex is probably not the best way to do this.

Upvotes: 1

user529758
user529758

Reputation:

Regexes ain't for extracting substrings. Why not use the dirname command?

$ dirname /home/foo/whatever.txt
/home/foo
$

If you need it in a variable:

DIRECTORY=`basename "SF_Library/example/Platform/DS-PLATFORM.car"`

Upvotes: 3

P.P
P.P

Reputation: 121407

You can use dirname command:

dirname SF_Library/example/Platform/DS-PLATFORM.car

It'll give you: SF_Library/example/Platform

Upvotes: 2

bobah
bobah

Reputation: 18864

You don't need a regex:

#!/bin/bash

fullpath="SF_Library/example/Platform/Analyses-PLATFORM.part0.xml"
# or if you read them then: while read fullpath; do

basename=${fullpath%/*}

# or if you read them then: done < input_file.txt

Upvotes: 8

Related Questions