Reputation: 11972
VB CODE.
dteFrom = Format(CDate(Year(Date) & "-" & Month(Date) & "-" & "01"), "yyyy-mm-dd")
dteTo = Format(CDate(Year(Date) & "-" & Month(Date) & "-" & DaysInMonth(dteFrom)), "yyyy-mm-dd")
I copy this code in VB.NET, It showing error (of Date)
dteFrom = Format(CDate(Year(Of Date)() & "-" & Month(Of Date)() & "-" & "01"), "yyyy-mm-dd")
dteTo = Format(CDate(Year(Of Date)() & "-" & Month(Of Date)() & "-" & DaysInMonth(dteFrom)), "yyyy-mm-dd")
Can any one Help to solve this problem.
Need VB.Net Code.
Upvotes: 0
Views: 8412
Reputation: 22442
This will be the closest to your original code:
dteFrom = Format(CDate(Year(Date.Today) & "-" & Month(Date.Today) & "-" & "01"), "yyyy-MM-dd")
dteTo = Format(CDate(Year(Date.Today) & "-" & Month(Date.Today) & "-" & Date.DaysInMonth(Year(Date.Today), Month(Date.Today))), "yyyy-MM-dd")
This will be a more ".NET" way to do it :
dteFrom = String.Format("{0:yyyy-MM}-01", Date.Today)
dteTo = String.Format("{0:yyyy-MM}-{1:00}", Date.Today, Date.DaysInMonth(Year(Date.Today), Month(Date.Today)) )
Upvotes: 1
Reputation: 8849
Something like:
Dim dateString as String = string.format("{0:yyyy-MM-dd}", New DateTime(DateTime.Now.Year,DateTime.Now.Month, 1))
Upvotes: 0
Reputation: 128317
It looks like you want two strings representing the first and last days of the current month. In that case you can do the following:
Dim today As Date = Date.Today
Dim desiredFormat As String = "yyyy-MM-dd"
Dim fromDate As Date = New Date(today.Year, today.Month, 1)
Dim dteFrom As String = fromDate.ToString(desiredFormat)
Dim toDate As Date = fromDate.AddDays(Date.DaysInMonth(today.Year, today.Month) - 1)
Dim dteTo As String = toDate.ToString(desiredFormat)
Upvotes: 4