CODEWITHSUNDEEP
mysqlsumaverage
Tony
Tony

Reputation: 1276

MySQL Average on a sum

Here is my problem:

I got a table like this one:

 Table Log
 int id;
 int time;
 timestamp DATE;
 int sid (FK to table Site);

and a table Site:

 Table Site;
 int id;
 varchar title;

In my log table, a site can be present 0 or N times, I need to get the sum of time for each site.

This request is done and seems to work, now I need to get the site title and the average of the sum time for a specific period in my logs.

Here is my query:

SELECT site, AVG(sumtime)
FROM (
    SELECT Site.TITLE as site, SUM(time) as sumtime FROM Log
    INNER JOIN sites ON Site.ID = Log.sid
    WHERE Log.DATE between '2012-11-13' AND '2012-11-15'
    GROUP BY Site.TITLE
) AS t1
GROUP BY t1.site;

But the average seems to not be working in this case, the value i'm getting is a the sum i've computed in my subquery, any help?

EDIT:

Here is a data sample:

Site
1 SiteA
2 SiteB

Log
1 2500 "2012-11-14 07:00:01" 1
2 3500 "2012-11-14 07:10:01" 1
3 4500 "2012-11-14 07:12:01" 1
4 6500 "2012-11-13 10:10:01" 1
5 2500 "2012-11-14 08:00:01" 2
6 3500 "2012-11-14 10:10:01" 2
7 5500 "2012-11-13 12:10:01" 2

What I need now is, an average on the time sum on a period (let's say 2012-11-13 to 2012-11-14 for this example), so as for the expected datas:

Site, avg time sum
Site A, 8500
Site B, 5750

Upvotes: 0

Views: 6073

Answers (2)

Tony
Tony

Reputation: 1276

I solved my problem, found the good way to write the query (thanks to @tombom):

SELECT t1.site, AVG(sumtime)
FROM (
    SELECT Site.TITLE as site, SUM(time) as sumtime FROM Log
    INNER JOIN Site ON Site.ID = Log.sid
    AND Log.DATE between '2012-11-14' AND '2012-11-15'
    GROUP BY site, DATE(Log.DATE)
) AS t1
group by t1.site

Upvotes: 6

SRIRAM
SRIRAM

Reputation: 1888

try this

SELECT t1.site, AVG(t1.sumtime)
FROM (
SELECT Site.TITLE as site, SUM(time) as sumtime FROM Log
INNER JOIN sites ON Site.ID = Log.sid
WHERE Log.DATE between '2012-11-13' AND '2012-11-15'
GROUP BY time
) AS t1
GROUP BY t1.site;

Upvotes: -1

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