CODEWITHSUNDEEP
rmatrix
user1723765
user1723765

Reputation: 6409

Calculating standardized difference for values in a matrix using R

I have a large matrix consisting of 116 columns and 4700 rows.

For each row I would like to compute a standardized difference of the following form:

(((a2-a1)/a1)*100)+100, where a1 is the previous value and a2 is the next value.

In R I'm using the following code:

for i in (1:116)

a[i]=(((a[i]-a[i-1])/a[i-1])*100)+100

However I get the following error:

Error in Ops.data.frame(a[i], a[i - 1]) : 
- only defined for equally-sized data frames

I'm guessing that the problem is that it does not take into account the very first value, where there does not exist a first value-1 to substract.

How can I solve this problem?

Here's a subset of the data: https://dl.dropbox.com/u/22681355/su.csv

Remember that I would like to calculate for each column individually!

Upvotes: 0

Views: 610

Answers (1)

Sacha Epskamp
Sacha Epskamp

Reputation: 47582

Your question could use a reproducible example to make it clearer. For example, you say you have a matrix but then show an error that is related to data frames. Without knowing what your data looks like we can not know if answers are correct.

But anyway, I think you can do this without loops as follows.

# Example data:
foo <- data.frame(A = 1:10, B = rnorm(10))

# Compute standardized differences:
(foo[-1,] - foo[-nrow(foo),]) / foo[-nrow(foo),] * 100 + 100

Upvotes: 1

Related Questions