C++ equivalent for C

Question

Program for work with arrays in dynamic memory. Need equivalent for C. Can anybody help?

const int n = 6;
char **words = (char**) malloc(n *sizeof(char*));
for(int i = 0 ; i < n; i++)
    words[i] = (char*)malloc( 50 * sizeof(int));

for(int i = 0; i < n; i++) 
{
    cin>>words[i];
}

cout<<endl;
for(int i = 0; i < n; i++) 
{
    if(words[i][0] == 'q')
        cout<<words[i]<<endl;
}

Answer 1

As you wish:

    const int n = 6;
    char **words = (char**) malloc(n *sizeof(char*));

    int i = 0;

    for( i= 0 ; i < n; i++)
    {
        words[i] = (char*)malloc( 50 * sizeof(char));
    }

    for(i = 0; i < n; i++) 
    {
        scanf("%s", words[i]); 
    }

    printf("\n");

    for(i = 0; i < n; i++) 
    {
        if(words[i][0] == 'q')
            printf("%s\n", words[i]);

    }

Answer 2

The only C++ parts there are cin and cout; you can change them easily:

cin>>words[i];

becomes

scanf("%s", words[i]);

or

gets(words[i]);

while

cout<<words[i]<<endl;

becomes

puts(words[i]);

By the way, in the cin/scanf/gets you have a potential buffer overflow, since you are allocating space for 6 characters but you are accepting input of any length. You should do instead:

scanf("%6s", words[i]);

or (more maintainable, since it uses n directly)

fgets(words[i], n, stdin);

(although this will include the trailing \n in the string)

Answer 3

Use scanf("%s", &words[i]) to input data from stdin and printf("%s\n", words[i]) to output to stdout.

Answer 4

The only C++ features you are using are cin and cout. replace cin>>words[i] with gets(words[i]) and cout<<words[i]<<endl with puts(words[i]).