CODEWITHSUNDEEP
windows-7batch-file
bubble
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Reputation: 3526

How to do command line comparison?

I am trying to use the following set of commands

FOR /f %%B IN ('DIR %SOME_FOLDER_LOCATION%\*.html ^| FIND "File(s)"') DO SET cnt=%%B
ECHO %cnt%

and 

TYPE %SOME_TEXT_FILE_PATH% | FIND /V /C "abcxyzabczyx"

After this i need to compare the output from both the lines and based on that display some status something like:

IF [%cnt%]==['TYPE %SOME_TEXT_FILE_PATH% | FIND /V /C "xyzxyzxyzxyz"'] ECHO CORRECT

The second portion of comparison is repetition. Wrote it just to give you an idea.

Can anyone suggest how this can be done.

Upvotes: 0

Views: 190

Answers (2)

Aacini
Aacini

Reputation: 67296

To count the number of .html files, I would use this method:

SET cnt=0
FOR %%B IN (%SOME_FOLDER_LOCATION%\*.html) DO SET /A cnt=cnt+1
ECHO %cnt%

To count the number of finds, I would use this:

FOR /f %%B IN ('FIND /V /C "abcxyzabczyx" %SOME_TEXT_FILE_PATH%') DO SET finds=%%B

This way, to compare both numbers:

IF [%cnt%] == [%finds%] ECHO CORRECT

I hope it helps...

Upvotes: 1

Joey
Joey

Reputation: 354864

Do the first one twice with your different command lines, but set a different variable too. Then just compare the two variables.

Upvotes: 1

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