CODEWITHSUNDEEP
arraysscalafunctional-programming
madCode
madCode

Reputation: 3913

Scala: Reading a file line by line into Array of lists

I'm reading a file line by line and putting into a list. So, if my file has 10 lines, I have ten lists. Now, while doing this or after doing this, I want to add all the lists into an Array. So, I have an Array of Lists, without using "var", so essentially just 'val'. Here's what I have so far: 

    val fileLines = Source.fromFile(filename).getLines.toList

    for (line <- fileLines) {
    if (!line.isEmpty) 
     println((line.toList).filter(e => e != ' '))
    }

I'm just converting every line into a list and removing blank elements. How do I generate a Array of Lists from this? Array being of type val and not try var.

Upvotes: 3

Views: 8254

Answers (1)

jcern
jcern

Reputation: 7848

You could try something like this:

val myArray = fileLines.filterNot(_.isEmpty).map { line =>
    (line.toList).filter(e => e != ' ')
}.toArray

That will give you an array of list elements. You can remove the .toArray at the end if you want a List of Lists.

Upvotes: 8

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