CODEWITHSUNDEEP
phpmysqlcachingram
user115422
user115422

Reputation: 4710

use MySQL server as "cache"

I know this is a weird question but I have 2 servers, one a vps and another, a mysql host. Now my issue is that I want to try and lower the load on the vps as it is a startup 128mb vps.

Slight problem, what would be required to make the MySQL server work as if it were a cache, I have no access to anything on the MySQL server save the databases im given.

Will this require a separate database? please tell me so if it is possible i can ask my host to add another database.

Thanks!

Upvotes: 2

Views: 461

Answers (1)

Botond Balázs
Botond Balázs

Reputation: 2500

If you host a website on the VPS that uses MySQL as the database, a typical request goes like this:

  • the client makes a request to the web server running on your VPS
  • your script running inside the web server makes a database query
  • the database returns the query results
  • your script formats and prints the results
  • the results appear in the browser (client)

There is no way to make a request hit the database without going through the web server first.

If you want to lighten the load on the VPS you can make your script run faster. The most time-consuming part of most web applications is making database queries and waiting for the results. You can, in a lot of cases, avoid that by caching the results of your database queries on the VPS using an in-memory cache like memcached. Be careful with the memory settings though - be sure to set the maximum allocated memory to a sufficiently low setting because your server has very little memory.

Here is a basic example of caching the result of a SELECT query:

$cache = new Memcached();
$cache->addServer('localhost', 11211);

$article_key = "article[$article_id]";
$article = $cache->get($article_key);

if ($article === FALSE) {
    $statement = $conn->prepare("SELECT * FROM articles WHERE id = :id");
    $statement->exec(array('id' => $article_id));
    $result = $statement->fetchAll(PDO::FETCH_ASSOC);
    if (count($result) === 0) {
        // return a 404 status
    }
    $article = $result[0]; 
    $cache->set($article_key, $article);
}

// display the article

Upvotes: 2

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