CODEWITHSUNDEEP
sqlpostgresqlgreatest-n-per-group
Alan Ennis
Alan Ennis

Reputation: 145

sql select earliest date for multiple rows

I have a database that looks like the following;

circuit_uid   |  customer_name   | location      | reading_date | reading_time | amps | volts  |  kw  | kwh | kva  |  pf  |  key
--------------------------------------------------------------------------------------------------------------------------------------
cu1.cb1.r1    | Customer 1       | 12.01.a1      | 2012-01-02   | 00:01:01     | 4.51 | 229.32 | 1.03 |  87 | 1.03 | 0.85 |    15
cu1.cb1.r1    | Customer 1       | 12.01.a1      | 2012-01-02   | 01:01:01     | 4.18 | 230.3 | 0.96 |  90 | 0.96 | 0.84 |    16
cu1.cb1.s2    | Customer 2       | 10.01.a1      | 2012-01-02   | 00:01:01     | 7.34 | 228.14 | 1.67 | 179 | 1.67 | 0.88 | 24009
cu1.cb1.s2    | Customer 2       | 10.01.a1      | 2012-01-02   | 01:01:01     | 9.07 |  228.4 | 2.07 | 182 | 2.07 | 0.85 | 24010
cu1.cb1.r1    | Customer 3       | 01.01.a1      | 2012-01-02   | 00:01:01     | 7.32 | 229.01 | 1.68 | 223 | 1.68 | 0.89 | 48003 
cu1.cb1.r1    | Customer 3       | 01.01.a1      | 2012-01-02   | 01:01:01     | 6.61 | 228.29 | 1.51 | 226 | 1.51 | 0.88 | 48004

What I am trying to do is produce a result that has the KWH reading for each customer from the earliest (min(reading_time)) on that date, the date will be selected by the user in a web form.

The result would be/should be similar to; 

Customer 1   87
Customer 2   179
Customer 3   223

There are more than the number of rows per day shown here and there are more customers and the number of customers would change regularly.

I do not have much experience with SQL, I have looked at subqueries etc. but I do not have the chops to figure out how arrange it by the earliest reading per customer and then just output the kwh column.

This is running in PostgreSQL 8.4 on Redhat/CentOS.

Upvotes: 5

Views: 18444

Answers (3)

Erwin Brandstetter
Erwin Brandstetter

Reputation: 656724

This should be among the fastest possible solutions:

SELECT DISTINCT ON (customer_name)
       customer_name, kwh  -- add more columns as needed.
FROM   readings
WHERE  reading_date = user_date
ORDER  BY customer_name, reading_time

Seems to be another application of:

Upvotes: 3

Yogendra Singh
Yogendra Singh

Reputation: 34367

   SELECT rt.circuit_uid ,  rt.customer_name, rt.kwh
   FROM READING_TABLE rt JOIN  
       (SELECT circuit_uid, reading_time
       FROM READING_TABLE
       WHERE reading_date = '2012-01-02'
       GROUP BY customer_uid
       HAVING MIN(reading_time) = reading_time) min_time
   ON (rt.circuit_uid = min_time.circuit_uid 
      AND rt.reading_time = min_time.reading_time);

Parameterize the reading_date value in above query.

Upvotes: 0

user330315
user330315

Reputation: 

select customer_name,
       kwh,
       reading_date, 
       reading_time
from (
   select customer_name,
          kwh,
          reading_time,
          reading_date,
          row_number() over (partition by customer_name order by reading_time) as rn
   from readings
   where reading_date = date '2012-11-17'
) t
where rn = 1

As an alternative:

select r1.customer_name,
       r1.kwh, 
       r1.reading_date,
       r1.reading_time
from readings r1
where reading_date = date '2012-11-17'
and reading_time = (select min(r2.reading_time)
                    from readings
                    where r2.customer_name = r1.customer_name
                    and r2.read_date = r1.reading_date);

But I'd expect the first one to be faster.

Btw: why do you store date and time in two separate columns? Are you aware that this could be handled better with a timestamp column?

Upvotes: 3

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