CODEWITHSUNDEEP
ruby-on-railsyieldcontent-for
Maximus S
Maximus S

Reputation: 11095

Rails: Using Yield, Calling Multiple View Pages

Problem: How Do You Render Multiple View Pages From Different Controllers?

In my views/layouts/application.html.erb, I call views/posts/index.html.erb with the yield method.

<div class='span10'>
    <%= yield %>
</div>

On top of it, I wanted to call views/good_posts/index.html.erb with yield. So in that particular index file, I wrap around all the code with content_for method. 

<%= content_for :good_post do %> all my content in good_post/index.html.erb <% end %>

I go back to application.html.erb, I tried to call the index file of good_post with yield method.

<div class='span10'>
    <%= yield :good_post %>
</div>
<div class='span10'>
    <%= yield %>
</div>

I thought this would result in good_post/index to be rendered on top of post/index, but it did not work; only post/index was correctly rendered as before. Could someone explain why this is, and tell me the correct way to approach this problem? I appreciate your help!

Upvotes: 2

Views: 1814

Answers (1)

Thanh
Thanh

Reputation: 8604

You should, as @cdesrosiers said, rename the index.html.erb file in good_posts to _index.html.erb. Then you can render this view in your application like this:

<div class='span10'>
    <%= render 'good_posts/index' %>
    <%= yield :good_post %>
</div>
<div class='span10'>
    <%= yield %>
</div>

Personally, I would change the index.html.erb file in good_posts folder to _good_posts.html.erb file in app/views/posts folder. Your code will have better meaning, and you can know where to find it after, because it relates to posts. So, if you change this, use this code:

<div class='span10'>
    <%= render 'posts/good_posts' %=
    <%= yield :good_post %>
</div>
<div class='span10'>
    <%= yield %>
</div>

Another you should change is content_for :good_post -> content_for :good_posts , because good posts maybe have many posts, so you should use post in pluralize.

Upvotes: 1

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