Reputation: 1309
Hi all, i am concatenating a JSON
string like this:
var addresses = "[";
addresses += '{"AddressID":' + adressid + ',"EmailID":' + $('#txtemailData').val() + ',"Hno":' + $('#txthno').val() + ',"StreetName":' + $('#txtstreetname').val() + ',"City":' + $('#txtcity').val() + ',"StateID":' + $('#ddlState').val() + ',"CountryID":' + $('#ddlcountry').val() + ',"Zip":' + $('#txtzip').val() + ',"PhoneNumber":' + $('#txtphonenumber').val() + ',"Fax":' + $('#txtfax').val() + ',"AddressName:' + $('#txtaddresstype').val() + '"},';
And the object looks like this:
[{
"AddressID":2,
"EmailID":[email protected],
"Hno":Hyderabad,
"StreetName":Gachibowli,
"City":Hyderabad,
"StateID":1,
"CountryID":1,
"Zip":040,
"PhoneNumber":8341516166,
"Fax":23123131,
"AddressName:Store Address"},
{
"AddressID":3,
"EmailID":[email protected],
"Hno":aSAs,
"StreetName":asdasdad,
"City":asdasda,
"StateID":1,
"CountryID":1,
"Zip":asdasda,
"PhoneNumber":asdasda,
"Fax":asdasda,
"AddressName:Store Type"
}]
How can I update this particular value of json object based on it's id?
Suppose I want to change some of the values of my object
where AddressID=2
. For example, I want to change the EmailID
,Streetname
of JSON
objects where AddressID=2
. How can I do this using jQuery?
I am trying it like this, but it's not going in the loop, Can any one help me here please?
function EditAddress(addressid) {
alert(addressid);
alert(addresses);
var addressobject =JSON.parse(addresses.substring(0, addresses.length - 1) + ']');
jQuery.each(addressobject, function (i, val) {
alert(val.AddressID);
if (val.AddressID == addressid)
{
//update logic
}
});
}
Upvotes: 1
Views: 14948
Reputation: 73906
You can just loop through the array arr
using the $.each()
function, then search for where id
property value is 2
. If found then update the required property in the object obj
and then break out of the loop like:
var arr = [
{"id": 1, "name": "Apple" , "isVisible": false},
{"id": 2, "name": "Orange", "isVisible": false},
{"id": 3, "name": "Banana", "isVisible": false}
]
$.each( arr, function( i, obj ) {
if(obj.id === 2){
console.log("Current " + obj.id + " = " + obj.isVisible);
obj.isVisible = true;
console.log("Changed " + obj.id + " = " + obj.isVisible);
return false; // Loop will stop running after this
}
});
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/1.7/jquery.min.js"></script>
Upvotes: 3
Reputation: 2493
use linq.js javascript library or jquery plugin: http://linqjs.codeplex.com/
<!DOCTYPE>
<html>
<head>
<script type="text/javascript" src="linq.js"></script>
</head>
<body>
<script>
var array = [{
AddressID:2,
EmailID:'[email protected]',
Hno:'Hyderabad'
},
{
AddressID:3,
EmailID:'[email protected]',
Hno:'aSAs'
}];
Enumerable.From(array).Where("$.AddressID == 3").ToArray()[0].Hno= 'ololo';
// or this:
// Enumerable.From(array).Where(function(x){return x.AddressID == 3}).ToArray()[0].Hno= 'ololo';
alert(array[1].Hno)
</script>
</body>
</html>
Upvotes: -1
Reputation: 21742
Firstly don't create the string by hand. It's a lot more robust to use build-in features so do this:
var addressesAsArray = [],
addressAsObject = {}
address;
//assuming some loop or other
address = {
"AddressID": adressid,
"EmailID":$('#txtemailData').val(),
"Hno":$('#txthno').val(),
"StreetName": $('#txtstreetname').val(),
"City": $('#txtcity').val(),
"StateID": $('#ddlState').val(),
"CountryID": $('#ddlcountry').val(),
"Zip": $('#txtzip').val(),
"PhoneNumber": $('#txtphonenumber').val(),
"Fax": $('#txtfax').val(),
"AddressName": $('#txtaddresstype').val()
};
addressesAsArray.push(address);
addressAsObject[address.AddressID] = address;
if you need to find an address with a given ID the approach would depend on whether you are looking in addressesAsArray or in addressesAsObject. The latter is straight forward
address = addressesAsObject[addressIDBeingSought];
in the array case you can simply loop
for(i = 0, len = addressesAsArray.length;i<len; i += 1){
if(addressesAsArray[i].AddressID === addressIDBeingSought) {
address = addressesAsArray[i];
break;
}
}
when you are done with the updating you can then get that as JSON by
json = JSON.stringify(adresses);
Upvotes: 0