CODEWITHSUNDEEP
javaurlservletsparameters
Thevagabond
Thevagabond

Reputation: 323

Retrieving parameters in URL with Java

I have a little Servlet that uses XSL and XML to generate PDF. Since I want to specify the files via URL I need to get those Parameters from there:

localhost/Servlet?xml=c:\xml\test.xml&xsl=c:\xsl\test.xsl

so the parameters that I need are

 c:\xml\test.xml
 c:\xsl\test.xsl

and those need to be read into the variables xml-file and xsl-file.

I have this but that doesn't really help me I guess since I don't know how to apply the values into the variables:

Map para = request.getParameterMap();
java.util.Iterator it = params.keySet().iterator();

while ( it.hasNext() )
{
    String key = (String) it.next();
    String value = ((String[]) para.get( key ))[ 0 ];
}

Any idea on how to do that?

Thanks,

TheVagabond

Upvotes: 5

Views: 24513

Answers (4)

Brian Agnew
Brian Agnew

Reputation: 272427

I think you simply want request.getParameter(String param)

e.g. 

String xml = request.getParameter("xml");

Note (for future reference) that the above won't handle multiple xml parameters. For that you should use request.getParameterValues(String param)

As noted above you probably shouldn't be passing filenames around. In preference I would upload the file, generate the PDF and make that available (simply via the response, or perhaps store it local to your servlet deployment and return an id for later retrieval?)

Upvotes: 3

Zutty
Zutty

Reputation: 5377

You can just get parameters by name with HttpServletRequest.getParameter()...

String xml-file = request.getParameter("xml");
String xsl-file = request.getParameter("xsl");

Upvotes: 2

couatl
couatl

Reputation: 416

In SERVLET must be request, yes?

String xml_path= request.getParameter("xml");

String xsl_path=request.getParameter("xsl");

Upvotes: 6

Ben Thurley
Ben Thurley

Reputation: 7161

What's wrong with this? 

String xsl = request.getParameter("xsl");
String xml = request.getParameter("xml");

Upvotes: 2

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