CODEWITHSUNDEEP
phpfunctionmenureturn
Stanislas Piotrowski
Stanislas Piotrowski

Reputation: 2694

function in php for displaying a menu

I met some trouble with a function I have written.

In fact I have an array in which I have different custom values.

I would like to display the result of that, so here is my function

function getAccess($var){
   $data=mysql_fetch_array(mysql_query("SELECT * FROM `acces` WHERE `id`='.$var.'")); 
   return $data;
}
getAccess($_SESSION['id']);

    $paramAcces = array(
        'comptesfinanciers' => array(
            'libelle'   => 'COMPTES FINANCIERS',
            'acces'     => $data['comptesfinanciers'],
            'lien'      => 'financier',
            'image'     => 'images/finances.png'
        )
    );

I have done a var_dump of $paramAcces which return

array(1) { ["comptesfinanciers"]=> array(4) { ["libelle"]=> string(18) "COMPTES FINANCIERS" ["acces"]=> NULL ["lien"]=> string(9) "financier" ["image"]=> string(19) "images/finances.png" } } (that are the ecpected values).

Here is the function for displaying what is in the array

/**
 * AFFICHAGE DE LA SECTION PARAMETRES SUR LA PAGE D'ACCUEIL
 */
 function affichParam($paramAccees){

     echo '<ul class="getcash-vmenu"><li><a href="index.php?p='.$paramAccees['lien'].'" class="active"><span class="t"><img src="'.$paramAccees['image'].'"> '.$paramAccees['libelle'].'</span></a></li></ul>';
 }

The trouble is that actualy it return to me an empty line.

I really do not know what I'm wrong doin:

I call the function like that:

<?php
affichParam($paramAccees)
?>

In a second time I will add more value, so I think I will have to do a for each loop or something like that.

But actualy I just would like to display the first record.

Any kind of help will be much apprecitaed

Upvotes: 0

Views: 64

Answers (1)

Samuel Cook
Samuel Cook

Reputation: 16828

lien is apart of the comptesfinanciers array which is apart of the paramAccees array, which should be reflected as so:

echo '<ul class="getcash-vmenu"><li><a href="index.php?p='.$paramAccees['comptesfinanciers']['lien'].'" class="active"><span class="t"><img src="'.$paramAccees['comptesfinanciers']['image'].'"> '.$paramAccees['comptesfinanciers']['libelle'].'</span></a></li></ul>';

Upvotes: 2

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