Reputation: 33
My issue is that when I click my button, it will work properly, but if I use the enter button, it will attempt to submit the form and appends a ?var=x to the URL.
My two inputs:
<input type="text" name="users" onkeydown="if (event.keyCode == 13) document.getElementById('submitbtn').click()">
<input type="button" name="submitbtn" onclick="showUser(users.value)">
You may view my source for the rest. If you put in 1 or 2 and click the button, you will get results, but if you hit enter, it will not give you results and changes the URL as I said.
http://crystalarcade.com/shoutbox
Upvotes: 1
Views: 2863
Reputation: 2585
I am assuming you will have a form with just two input elements. With jQuery you can do something like this:
Some thing like this should get you started with, I need make a note however that this code is untested because I cannot do cross-site request using AJAX.
<script type="text/javascript">
$(function(){
$("#username").on("keypress", function(e){
if(e.keyCode==13){ //keyCode value of 13 is for the enter key
$.get("getusers.php" $("#userSearchForm").serialize(), function(data){
if(data){
$("shoutboxtxt").text(data);
}
}, "text");
}
}
});
</script>
<form id="userSearchForm">
<input type="text" name="users" id="username" />
<input type="button" name="submitbtn" id="submitbtn" value="Search" />
</form>
<div id="shoutboxtxt"><b>Person info will be listed here.</b></div>
Online here: http://jsfiddle.net/HwcN3/1/
Upvotes: 0
Reputation: 7663
you are using document.getElementById
so give your button an id
like this
<input type="text" name="users" onkeydown="if (event.keyCode == 13) document.getElementById('submitbtn').click()">
<input type="button" id="submitbtn" name="submitbtn" onclick="showUser(users.value)">
and this will work for you
Upvotes: 4