CODEWITHSUNDEEP
c++linuxgccg++
skyel
skyel

Reputation: 763

‘ostream’ in namespace ‘std’ does not name a type

As the title suggests I'm experiencing a rather odd problem. When I try to compile a sample source code (that uses libotb) I keep getting errors like the one in the title. What is weird is that #include <iostream> is present in the said source/header where the error is reported.

On the other hand if I extract the code from the said file and create a separate source and compile it with g++ <source_file> it works, but if I compile with g++ -I<path_to_libotb_headers> <source_file> I get the same error, although the source file doesn't include anything from said path.

As stated in the below comments, this issue happens with simply 

#include <iostream>   

int main                                                                                
{
    std::cerr << "Test";
    return 0;
}

Upvotes: 7

Views: 23490

Answers (4)

m2mm4m
m2mm4m

Reputation: 1

If you are an Arduino programmer don't forget that Arduino does NOT have any normal ‘ostream’ stuff build-in.
But there is libraries offering similar functions.

PS. Bear in mind that there is good reasons that streaming type stuff is not included.

Upvotes: 0

Luke
Luke

Reputation: 39

It should be:

int main ()

  • you missed the () :)

Upvotes: 3

Pete Becker
Pete Becker

Reputation: 76235

#include <ostream>

should fix it. Under C++11, #include <iostream> is supposed to pull in all of <ostream>, but prior to C++11 you had to do the individual #includes.

Upvotes: 8

justin
justin

Reputation: 104698

Verify that your includes all closed their namespaces -- your include may accidentally be declared in a namespace if a previous header did not close its namespaces.

You can also attempt to locate this problem by moving the std includes earlier in the include list.

Upvotes: 1

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