CODEWITHSUNDEEP
c#
Roman Ratskey
Roman Ratskey

Reputation: 5259

Creating Range Table

First the thread name might be a little strange but i will try my best to explain what i want to do here so you can suggest me a good thread name.

I want to create a function to return the employee level by checking his experience

If experience is 0~50 he is level 1 If experience is 50~150 he is level 2 ... and so on till level 100

What i am thinking of is creating a const int that holds all required exp for each level 

public const int Level1 = 50,
                 Level2 = 150...;

so is there a way to make a function to return what i want ? without the use of 1000++ lines ?!.

Please don't consider my question as a spam i am only very confused and i will try my best to clarify my idea if needed.

Upvotes: 1

Views: 137

Answers (3)

hoang
hoang

Reputation: 1917

Since the formula for the xp required for the level x seems to be 25*(x²+x)

You can use the inverse function :

public int GetLevel(int xp)
{
    return (int)(Math.Sqrt(1 + 4 * xp / 25) - 1) / 2;
}

Upvotes: 1

René Wolferink
René Wolferink

Reputation: 3548

int level = Math.Min(10, experience / 10);

Would that do?

If you want to have 0-10 -> 1 and 11-20 -> 2 etc, change it like this:

int level = Math.Min(10, (experience + 9) / 10);

If there is no pattern at all in experience gains, or some very obscure one, you could use this:

var level = 1;

var levelRequirements = new int[] {10, 20, 50, 150, 300};
for (int i = 0; i < levelRequirements.Length; i++)
{
    if (levelRequirements[i] > currentExperience)
        break;
    level++;
}

And now for my final update:

var level = 0;

var levelRequirement = 0;
var levelRequirementAddition = 50;

while (currentExperience >= levelRequirement)
{
    levelRequirement += levelRequirementAddition;
    levelRequirementAddition += 50;
    level++;
}

Upvotes: 2

Sam I am says Reinstate Monica
Sam I am says Reinstate Monica

Reputation: 31184

public int ReturLevel(int experience)
{
    return (experience-1)/10 + 1;
}

you may remove the -1 in (experience-1) if you meant "If experience is 1~9"

leave it if you meant "If experience is 11~20 he is level 2"

Edit:

IF your experience to level function doesn't follow any pattern, than Yes, you'll have to make a separate case for each one of them. 

if(experience > 20)
    return level 3;
else if(experience > 10)
    return level 2;
else
    return level 1;

different design patterns can affect how and were you add these different cases, but they'll have to be added if you have no pattern.

Upvotes: 1

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