Reputation: 19837
alright well I have the follow function
y=sin(x)^2 + [(10+2x+x^2) / (5+2x^2)]
i need to plot it on the interval y = -2 to y = 2 so how would I set that up?
I did this in matlab
>> y = sin(x).^2 + (10 + 2*x + x.^2)/(5+2*x.^2)
>> x = -2:0.01:2;
is that a correct setup? Or have I done something wrong
Upvotes: 0
Views: 23853
Reputation: 39698
You need to declare a variable before you use it. In this case, x doesn't depend on y, so declare it first. In addition, there is a ./
operator missing.
x = -2:0.01:2;
y=sin(x).^2 + (10+2*x+x.^2) ./ (5+2*x.^2);
plot(x,y)
Upvotes: 7