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c#linqienumerable
litterbugkid
litterbugkid

Reputation: 3666

Returning IEnumerable<string> from Linq query

I'm trying to return an IEnumerable<string> from a linq query and I'm getting the error: Cannot convert IEnumerable<AnonymousType> to IEnumerable<string>

I have no idea how to go about fixing this issue.

private IEnumerable<string> GetAllMembers(Type type)
        {    

            var query =
                (from member in type.GetMembers()
                 select new
                 {
                     Member = member.GetType() + " " + member.ToString()

                 }
                );

            return query;
        }

Upvotes: 2

Views: 10194

Answers (4)

Justin Harvey
Justin Harvey

Reputation: 14672

Try this

private IEnumerable<string> GetAllMembers(Type type)
    {    

        var query =
            from member in type.GetMembers()
             select member.GetType() + " " + member.ToString();

        return query;
    }

You were creating an IEnumerable of anonymous types, when I think you just wanted an enumeration of strings.

Upvotes: 5

Jamiec
Jamiec

Reputation: 136114

The problem is your query returns an anonymous object with one property Members which is a string, simply change to just returning the string:

 var query =
            (from member in type.GetMembers()
             select member.GetType() + " " + member.ToString()
            );

  return query;

Upvotes: 2

Jan
Jan

Reputation: 16042

You are returning an anonymous type (constructed by new {}) from your query and not a string. You can modify the query like this for example, so the result is an IEnumerable<string>:

return from member in type.GetMembers()
       select member.GetType() + " " + member.ToString();

Upvotes: 2

Sergey Berezovskiy
Sergey Berezovskiy

Reputation: 236228

You are creating anonymous type with Member property. Simply return string values thus you are expect IEnumerable<string>

private IEnumerable<string> GetAllMembers(Type type)
{    
    return from member in type.GetMembers()
           select member.GetType() + " " + member.ToString();
}

Upvotes: 3

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