Reputation: 63
How to write a function counting number of letter in list? for example:
letter_list=['a','b','a','c','b','a']
letter_index={'a':0,'b':1,'c':2}
I want to get a result of:
([3,2,1])
Upvotes: 0
Views: 188
Reputation: 29093
Just one small option:
letter_list=('a','b','a','c','b','a')
def __get_res(lVals):
unique = set(lVals)
res = map(lVals.count, unique)
return (max(unique, key=lVals.count), map(lVals.count, unique))
print __get_res(letter_list)
Upvotes: 0
Reputation: 18848
Try using dict comprehension. Also, letter_list
in your example is a tuple
, not a list
.
>>> letter_list = ['a','b','a','c','b','a']
>>> {x:letter_list.count(x) for x in letter_list}
{'a': 3, 'c': 1, 'b': 2}
To get the highest occurring item in the list, you could use the Counter
module as detailed by @BoppreH, or you could do something like this.
>>> max(set(letter_list), key=letter_list.count)
'b'
Upvotes: 0
Reputation: 10173
To get the most common items in a list, or just count the number of occurrences, use the Counter class.
from collections import Counter
letter_list=('a','b','a','c','b','a')
counter = Counter(letter_list)
print counter.most_common(1)
# Prints 'a' because it's the most common element
And from this you can also get the number of occurrences of each element:
print counter['a'] # Prints 3
print counter.most_common() # Prints [('a', 5), ('r', 2), ('b', 2)]
Upvotes: 1