CODEWITHSUNDEEP
pythongoogle-app-enginerest
Peter Warbo
Peter Warbo

Reputation: 11710

Google App Engine Python - Simple REST handler

I have a scenario where a client (mobile app) would send an update query to my GAE website to see if the website has a newer version of a resource and if it does it would return this resource (zip-file) otherwise it would just return a json response "all up to date" (or perhaps a Not Modified 304 HTTP response code)

How should the REST URL look (coming from the mobile app)?

www.example.com/update?version=(client_version)

OR

www.example.com/update_client_version

Thankful for any help I can get.

What I have so far is... but I'm getting a 404 for some reason when doing http://localhost:8080/update/1

INFO 2012-11-22 10:12:18,441 dev_appserver.py:3092] "GET /holidays/1 HTTP/1.1" 404 -

class UpdateHandler(webapp2.RequestHandler):
    def get(self, version):

        latestVersion == 1

        if version == latestVersion:
            self.response.write('You are using latest version')
        else:
            self.response.write('You are not using latest version')


app = webapp2.WSGIApplication([('/update/(.*)', UpdateHandler)], debug=True)

Upvotes: 3

Views: 1558

Answers (2)

Thanos Makris
Thanos Makris

Reputation: 3115

I would go with the following approach:

www.example.com/update/client_version

Your code should look like this:

import webapp2

class UpdateHandler(webapp2.RequestHandler):
    def get(self, version):
        # Do something for version

app = webapp2.WSGIApplication(
    [(r'/update/(\d+)', UpdateHandler)], 
    debug=True)

Upvotes: 2

Hans Then
Hans Then

Reputation: 11322

If you intend to use HTTP 304, you should see if you can get the client to make a conditional GET request. E.g. add a header If-Modified-Since: Thu, 22 Nov 2012 09:24:52 GMT.

Upvotes: 1

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