CODEWITHSUNDEEP
c#regex
2pietjuh2
2pietjuh2

Reputation: 879

Make Regex stop looking at \n

I have the following string: 

"\t Product:         ces DEVICE TYPE \nSometext" //between ":" and "ces" are 9 white spaces

I need to parse the part "DEVICE TYPE". I'm trying to do this with Regex. I use this expression, which works.

((?<=\bProduct:)(\W+\w+){3}\b)

this expression returns:

"         ces DEVICE TYPE"

The problem is here: Some devices have a string like this: 

"\t Product:         ces DEVICETYPE \nSometext"

If I use the same expression to parse the device type I get this as result:

"         ces DEVICETYPE \nSometext"

How do I get my regex to stop when a \n is found?

Upvotes: 2

Views: 825

Answers (3)

Cylian
Cylian

Reputation: 11182

You could use:

(?m)((?<=\bProduct:).+)

Explanation:

(?m)((?<=\bProduct:).+)

Match the remainder of the regex with the options: ^ and $ match at line breaks (m) «(?m)»
Match the regular expression below and capture its match into backreference number 1 «((?<=\bProduct:).+)»
   Assert that the regex below can be matched, with the match ending at this position (positive lookbehind) «(?<=\bProduct:)»
      Assert position at a word boundary «\b»
      Match the characters “Product:” literally «Product:»
   Match any single character that is not a line break character «.+»
      Between one and unlimited times, as many times as possible, giving back as needed (greedy) «+»


or

    ((?<=\bProduct:)[^\r\n]+)

Explanation

((?<=\bProduct:)[^\r\n]+)

Match the regular expression below and capture its match into backreference number 1 «((?<=\bProduct:)[^\r\n]+)»
   Assert that the regex below can be matched, with the match ending at this position (positive lookbehind) «(?<=\bProduct:)»
      Assert position at a word boundary «\b»
      Match the characters “Product:” literally «Product:»
   Match a single character NOT present in the list below «[^\r\n]+»
      Between one and unlimited times, as many times as possible, giving back as needed (greedy) «+»
      A carriage return character «\r»
      A line feed character «\n»

Upvotes: 1

Buh Buh
Buh Buh

Reputation: 7545

In .NET you can use RegexOptions.Multiline. This changes the behaviour of ^ and $.
Rather than meaning the start and end of your string, they now mean start and end of any line within your string.

Regex r = new Regex(@"(?<=\bProduct:).+$", RegexOptions.Multiline);

Upvotes: 2

Simon Whitehead
Simon Whitehead

Reputation: 65059

Perhaps this?

(?<=ces)[^\\n]+

If all you want is what's after ces and before \n that is..

Upvotes: 2

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