CODEWITHSUNDEEP
javascriptregex
Infotechie
Infotechie

Reputation: 1653

escape carret sign '^' in regular expression

In form there is a text field in which I want to restrict '^' sign. I am trying to escape carret sign '^' in regular expression. For e.g.

"abcdef".match([^]) is returning true

please provide suggestion.

Upvotes: 0

Views: 100

Answers (4)

Bruno
Bruno

Reputation: 5822

If you just want to check if the string contains a caret try

/\^/.test( "abcdef" ); // => false
/\^/.test( "^abcdef" ); // => true
/[^\^]/.test( "aslkfdjfs" ); // =>true as caret does not exist in string

Upvotes: 0

harikrishnan.n0077
harikrishnan.n0077

Reputation: 2067

Use .search(/\^/) .Backslash '\' will remove the function of '^' .This way you can restrict.

Upvotes: 1

Kos
Kos

Reputation: 72279

To match the line beginning:

> 'abcdef'.match(/^/)
[ '', index: 0, input: 'abcdef' ]

To match literal ^, escape it:

> 'abcdef'.match(/\^/)
null

To match literal ^ inside a class of characters, put it on any position except the first:

> 'abcdef'.match(/[xyz^]/)
null
> 'abcdef'.match(/[def^]/)
[ 'd', index: 3, input: 'abcdef' ]

Upvotes: 3

J0HN
J0HN

Reputation: 26951

Syntax error. Regexes must be enclosed in / in JS, so it should be

"abcdef".match("/[^]/"); //gives null

Also, you don't need to embrace the / into a [], you can just escape it with \:

"abcdef".match("/\^/"); //gives null

See the http://www.regular-expressions.info/javascript.html for details

Upvotes: 0

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