CODEWITHSUNDEEP
python
Viswa
Viswa

Reputation: 171

How do i convert date as time format in python?

My code is:

import datetime
tomorrow = datetime.date.today() + datetime.timedelta(days=1)
print "Tomorrow date is" + str(tomorrow) 
tm_stme = datetime.time(0, 0, 0)
tm_etime = datetime.time(23,59,59)
tm_stdate = datetime.datetime.combine(tomorrow, tm_stme)
tm_enddate = datetime.datetime.combine(tomorrow,tm_etime)

print "tomorrow start date:" + str(tm_stdate)
print "tomorrow end date:" + str(tm_enddate)  

tm_sdt_convert = time.mktime(time.strptime(tm_stdate, "%Y-%m-%d %H:%M:%S"))
tm_tdt_convert = time.mktime(time.strptime(tm_enddate, "%Y-%m-%d %H:%M:%S"))

And the error is:

administrator@Ashok-Dev:~/Desktop$ python testing.py 
Tomorrow date is2012-11-24
tomorrow start date:2012-11-24 00:00:00
tomorrow end date:2012-11-24 23:59:59
Traceback (most recent call last):
  File "testing.py", line 17, in <module>
    tm_sdt_convert = time.mktime(time.strptime(tm_stdate, "%Y-%m-%d %H:%M:%S"))
  File "/usr/lib/python2.6/_strptime.py", line 454, in _strptime_time
    return _strptime(data_string, format)[0]
  File "/usr/lib/python2.6/_strptime.py", line 322, in _strptime
    found = format_regex.match(data_string)
TypeError: expected string or buffer

I need the value of tm_sdt_convert variable.

Upvotes: 1

Views: 1611

Answers (1)

dvdios
dvdios

Reputation: 76

time.strptime take a formatted string, its format and rerurn a tuple that contain datetime info. But you already have a datetime object whitch could by directly casted to tuple using method timetuple.

So correct code should be:

>>> tm_sdt_convert = time.mktime(tm_stdate.timetuple())
>>> tm_sdt_convert
1353711600.0

Correct strptime usage:

>>> time.mktime(time.strptime(str(tm_stdate), "%Y-%m-%d %H:%M:%S"))

Useful when you only have a string containing datetime.

Upvotes: 4

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