CODEWITHSUNDEEP
cforkexecvp
MOHAMED
MOHAMED

Reputation: 43518

How to get error of execvp in the fork()?

I have the following code.

My question is in the code

     int main() {

            ....

         if ((uproc.pid = fork()) == -1) {
            return -1;
        }

        if (uproc.pid == 0) {
            /* child */

            const char *argv[3];
            int i = 0;
            argv[i++] = "/bin/sh";
            argv[i++] =  "/my/script.sh";
            argv[i++] = NULL;

            execvp(argv[0], (char **) argv);
            exit(ESRCH);

        } else if (uproc.pid < 0)
            return -1;

        /* parent */
        int status;
        while (wait(&status) != uproc.pid) {
            DD(DEBUG,"waiting for child to exit");
        }

           // If /my/script.sh exit accidentally in some place with error. 
           // can I catch this error right here?
          ......
    }

Upvotes: 1

Views: 1377

Answers (1)

Some programmer dude
Some programmer dude

Reputation: 409166

The exit status of the child is provided by the wait function, in the status variable.

You get the exit status by using the WEXITSTATUS macro, but only if the program exited normally (i.e. called exit or returned from its main function):

if (WIFEXITED(status))
    printf("Child exit status: %d\n", WEXITSTATUS(status));
else
    printf("Child exited abnormally\n");

Read the manual page for wait for more information.

Upvotes: 4

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