CODEWITHSUNDEEP
csockets
Koumasi
Koumasi

Reputation: 21

What does (stuct sockadrr*)&servaddr mean?

I 've encountered this piece of code:

(stuct sockadrr*)&servaddr

What does that mean? You cast the struct somehow to servaddr?

I'm just trying to figure out the syntax of this code and the meaning of it in C.

Upvotes: 2

Views: 222

Answers (2)

chill
chill

Reputation: 16888

Various socket functions are declared to take as a parameter a generic network address, you cast the address of a specific network address struct (e.g. sockaddr_in) in order to pass it as a parameter to the function.

Upvotes: 2

Daniel Fischer
Daniel Fischer

Reputation: 183908

You cast the struct somehow to servaddr?

No, the other way round, you cast the address of servaddr to a pointer to struct sockaddr.

If servaddr has type foo, &servaddr is a foo*, a pointer to foo. If you call a function that expects a pointer to struct sockaddr, you need to cast it - if the types are compatible, so that passing a foo* as a struct sockaddr* works.

Upvotes: 3

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