CODEWITHSUNDEEP
vb.net
Omair Iqbal
Omair Iqbal

Reputation: 1838

calculating value of two variables in a percentage equation

i am trying to programmatically find value of x and y in equation 146 + x + y divided by 7 = 28.13% x and y contains any value between 19 and 43. here is the code i am getting 25 for both x and y ,what am i doing wrong?

Public Class Form1
    Dim percentage, x, y, f As Integer
    Public Function GetRandom(ByVal Min As Integer, ByVal Max As Integer) As Integer
        Dim Generator As System.Random = New System.Random()
        Return Generator.Next(Min, Max)
    End Function
    Private Sub Button1_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button1.Click
        percentage = 28.13

        Do Until f = 4
            If (146 + x + y) / 7 = percentage Then
                MessageBox.Show(x)
                MessageBox.Show(y)
                f = 4
            End If
            x = GetRandom(19, 43)
            y = GetRandom(19, 43)

        Loop


    End Sub

    Private Sub Form1_Load(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles MyBase.Load
        x = 19
        y = 19
    End Sub
End Class

Upvotes: 0

Views: 1527

Answers (2)

Andrew Morton
Andrew Morton

Reputation: 25013

You are looking for (x+y)=50.91 where x is in [19, 43] and y is in [19, 43].

Therefore, choose an x, and then y=50.91-x

There is no single solution to the equation you have shown.

Or are you actually asking for something else?

Upvotes: 2

LarsTech
LarsTech

Reputation: 81610

1) You declared percentage as an integer but are trying to set it to 28.13, which is not an integer.

2) Don't keep recreating a new random object:

Public Class Form1
  Private Generator As New Random()

  Public Function GetRandom(ByVal Min As Integer, ByVal Max As Integer) As Integer
    Return Generator.Next(Min, Max)
  End Function

3) If you have to equal 28.13, then that probably won't work without declaring percentage as a decimal and then using Math.Round(...) on your equation, but even then, I don't think you will have any x and y integers that will satisfy the equation for precise equality.

Upvotes: 2

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