Reputation: 41
I need to get a percentage for 75 values in 75 columns individually. And I want to use a do loop so I don't have to hard code it 75 times. There are some conditions so there will be a where statement.
I am not getting the do loop correctly but I am using the below to get a percentage
case when (SUM(t1.sam)) >0 then
((SUM(t1.sam))/(SUM(t1.sam_Threshold)))*100
else 0
end
I tried the below and its a bit better:
data test;
i_1=4;
i_2=8;
i_3=4;
i_4=8;
V_ANN_V_INSP=24;
run;
%macro loop();
%let numcols=4;
proc sql;
create table test3 as
select V_ANN_V_INSP,
%do i=1 %to &numcols;
(i_&i/V_ANN_V_INSP)*100 as i_&i._perc
%if &i<&numcols %then %do;,
%end;
%end;
from test;
quit;
%mend;
%loop();
Upvotes: 0
Views: 6673
Reputation: 63424
CASE WHEN is a SQL statement, not a data step statement, so you can't use a DO loop there. Depending on what you're doing exactly, there are a lot of possible solutions here. Posting additional code would help to get a more precise answer, but I can give you a few suggestions.
First, take it into a data step. Then you can use a do loop.
data want;
set have;
array nums sam1-sam75;
array denoms threshold1-threshold75;
array pct[75];
do _t = 1 to dim(nums);
pct[_t]=nums[_t]/denoms[_t];
end;
run;
Second, if you need to do this in SQL for some reason, you can write out the SQL code either in a macro or in a data step in a pre-processing step.
%macro do_sql_st;
%do _t = 1 to 75;
case when (SUM(t1.sam&_t.)) >0 then
((SUM(t1.sam&_t.))/(SUM(t1.sam_Threshold&_t.)))*100
else 0
end
as pct&_t.
%end;
%mend do_sql_st;
proc sql;
select %do_sql_st from t1 where ... ;
quit;
These are not terribly flexible; unless you have very specifically named variables, they won't work as is. You're more likely to want to do some sort of data step preprocessing I suspect, but that's very hard to explain without more detail as to how the variables are named (ie, if there is a relationship between them).
Upvotes: 2