CODEWITHSUNDEEP
pythongoogle-app-enginepython-2.7yaml
mike29892
mike29892

Reputation: 263

Python 2.7 GAE app.yaml Getting 404 Error

Below is the code of my app.yaml file. If I go to localhost:8080/ my index.app loads correctly. If I go to localhost:8080/index.html I get a 404 error. If I go to any other page for example localhost:8080/xxxx the not_found.app loads correctly. Why am I getting a 404 Error for the /index\.html case?

Thanks!

application: myapp
version: 1
runtime: python27
api_version: 1
threadsafe: true

handlers:
- url: /index\.html
  script: index.app

- url: /
  script: index.app

- url: /assets
  static_dir: assets

- url: /*
  script: not_found.app

libraries:
- name: jinja2
  version: latest

Code from index.py

class MainPage(webapp2.RequestHandler):

def get(self):

template = jinja_environment.get_template('index.html')

self.response.out.write(template.render(template_values))

app = webapp2.WSGIApplication([('/', MainPage)], debug=True)

The fix was located in the bolded text!

Upvotes: 1

Views: 1097

Answers (1)

RocketDonkey
RocketDonkey

Reputation: 37249

It looks like your app variable in index does not have a handler for index.html. For instance:

app = webapp2.WSGIApplication([('/', MainPage)])

If your application gets routed to index, it will look through the handlers defined and try to find a match to /index.html. In this example, if you go to /, it will work fine since that handler is defined; however if you go to index.html, GAE doesn't know which class to call, and it therefore returns a 404. As a simple test, try 

app = webapp2.WSGIApplication([
    ('/', MainPage),
    ('/index\.html', MainPage)
])

Since this is ostensibly a handler for anyone typing index.html or any other permutation of index., you could use something like this to capture a broader array of cases (because internally, you can just route using / if you need to):

app = webapp2.WSGIApplication([
    ('/', MainPage),
    ('/index\..*', MainPage)
])

Upvotes: 5

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