CODEWITHSUNDEEP
phparrays
Sola Adekunle
Sola Adekunle

Reputation: 13

print out two dimensional array php

I am trying to print out two dimensional arrays from the results of an sql statement in php

so far i have this code

for ($i=0; $i < count($searchResults); $i++) {
print "<tr>";
print "<td>";
print "$searchResults[$i]['username']";
print "</td>";
print "<td>";
print "<a href=\"viewprofile.php?email=$searchResults[$i]['email'] 
     \">$searchResults[$i]['email']</a>";
print "</td>";
print "</tr>";
  }

but instead of printing out the value in the array it prints out things like $array['username'] instead and i dont want to use for each loops since the second condition has to be a link any ideas?

Upvotes: 0

Views: 1613

Answers (3)

Raekye
Raekye

Reputation: 5131

It's having problems parsing array syntax. Just take out the double quotes

print $searchResults[$i]['username'];
print "<a href=\"viewprofile.php?email=" . $searchResults[$i]['email'] .
     "\">" . $searchResults[$i]['email'] . "</a>";

If you insist on having PHP parse, read more on string parsing http://php.net/manual/en/language.types.string.php

For array syntax, you don't need the quotes, eg

print "{$searchResults[$i][username]}";

(notice no quotes around 'username'). Don't work with variables though, unless you use those curly braces (again just read up). Better to just use concat

Upvotes: 0

akatakritos
akatakritos

Reputation: 9858

foreach ($searchResults as $result) {
    print "<tr>";
    print "<td>";
    print $result['username'];
    print "</td>";
    print "<td>";
    print "<a href=\"viewprofile.php?email=$result[email] 
         \">$result[email]</a>";
    print "</td>";
   print "</tr>";
}

Note that when embedding an array variable inside a " " string, you dont single quote escape the array keys. ($result[email] instead of $result['email']).

Upvotes: 0

Tim Withers
Tim Withers

Reputation: 12059

You can't do multidimensional arrays in a string the way you are doing it:

print "$searchResults[$i]['username']";
print "<a href=\"viewprofile.php?email=$searchResults[$i]['email'] 
 \">$searchResults[$i]['email']</a>";

Change them to this:

print $searchResults[$i]['username'];
print "<a href=\"viewprofile.php?email=".$searchResults[$i]['email']." 
 \">".$searchResults[$i]['email']."</a>";

Upvotes: 1

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