CODEWITHSUNDEEP
javaparsingjavaparser
Freewind
Freewind

Reputation: 198418

How to parse a method or any other valid expression using JavaParser

JavaParser is a java source code parsing tool. I read the documents but found it only able to parse source of a full java class, like:

public class X {
    public void show(String id) {
        Question q = Quesiton.findById(id);
        aaa.BBB.render(q);
    }
}

But I want to parse only part of it, e.g. the method declaration:

public void show(String id) {
    Question q = Quesiton.findById(id);
    aaa.BBB.render(q);
}

How to do it or is it possible? If not, is there any other tool can do this?

Update

Actually I want to parse any valid expression in java, so I can do this easily with JavaParser:

CompilationUnit unit = JavaParser.parse(codeInputStream);

addField(unit, parseField("public String name"));  // not possible now

Upvotes: 1

Views: 1230

Answers (1)

Hazem Elraffiee
Hazem Elraffiee

Reputation: 453

I see you can include the method in a dummy class and parse it as usual. For the example you provided, enclose it inside:

public class DUMMY_CLASS_FOO {

    // The string you're trying to parse (method or whatever)

}

Then you parse it as usual and neglect your dummy class while parsing.

UPDATE:

For the update you provided, you may try and catch

If the previous enclosure didn't do it, so enclose it into:

public class DUMMY_CLASS_FOO {

    public void DUMMY_METHOD_FOO {

        // Anything here

    }
}

You might also search for Access Level Modifiers (public, private, ...etc), and if found, do the 1st solution. If not found, do the other one.

Upvotes: 2

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