CODEWITHSUNDEEP
phpjavascriptajaxsubmitpage-refresh
Bkay
Bkay

Reputation: 177

how to run php code on submit button without refreshing/ reloading the page

I want to execute some php code on submit button click without refreshing/reloading my page. Is it possible? also i have javascript function on page load that's why i don't want to refresh my page. thanks in advance.

<?php
if(isset($_POST["search"]))
{
$show = "SELECT * FROM data";
$rs = mysql_query($show) or die(mysql_error());
 $add_to_textbox = "<input type='button' name='btn' value='add' />";
#****results in Grid****
    echo "<table width='360px' border='1' cellpadding='2'>";
    $rowID=1;
while($row = mysql_fetch_array($rs))
{
    echo "<tr>";
    echo "<td width='130px' id='name.$rowID.'>$row[Name]</td>";
    echo "<td width='230px' id='link.$rowID.'><a href = '$row[Link]'>$row[Link]</a></td>";
    echo "<td width='130px' onclick='Display($rowID);'>$add_to_textbox</td>";
    echo "</tr>";
    $rowID++;
}
    echo "</table>";
#**********************
mysql_free_result($rs);
}
?>

<script type="text/javascript">
function Display(rowID){
    var linkVal = document.getElementById('link'+rowID+'').innerHTML.replace(/<\/?[^>]+(>|$)/g, "\n");
    document.getElementById("name").value = document.getElementById('name'+rowID+'').innerHTML;
    document.getElementById("link").value = linkVal; 
    }
</script>

here is my code

Upvotes: 1

Views: 18321

Answers (3)

Pradeep
Pradeep

Reputation: 317

Your HTML or PHP form 

<form action="submit.php"  method="post">
Name: <input name="name" id="name" type="text" /><br />
Email: <input name="email" id="email" type="text" /><br />
Phone Number: <input name="phone" id="phone" type="text" /><br />
<input type="button" id="searchForm" onclick="SubmitForm();" value="Send" />
</form>

Your JavaScript 

 <script>
 function SubmitForm() {
 var name = $("#name").val();
 var email = $("#email").val();
 var phone = $("#phone").val();
 $.post("submit.php", { name: name, email: email, phone: phone },
 function(data) {
 alert("Data Loaded: " + data);
 });
 }
 </script>

Your PHP page to do some activity

 <?php
 echo $_POST['name']."<br />";
 echo $_POST['email']."<br />";
 echo $_POST['phone']."<br />";
 echo "All Data Submitted Sucessfully!"
 ?>

Upvotes: 0

Louis Loudog Trottier
Louis Loudog Trottier

Reputation: 487

Whenever you send request ajax (with plain js anyway) from a html form, make sure you add the return false statement to prevent redirection: something like:

<form method="post" ... onsubmit="ajax_post(); return false;">

You have to use ajax, but you can do it in plain javascript (without jquery). Jquery makes it easier.

plain javascript example: This function will trigger an ajax, via get, without parameter: you can tweak it so it run in POST and be able to send some parameter: file represent the php file to request and html represent the container whre the data will be displayed:

function plain_ajax(file,html){
    if (window.XMLHttpRequest){ 
          r=new XMLHttpRequest();   //For Most BRowser
    } else{ 
          r=new ActiveXObject("Microsoft.XMLHTTP");  //for Explorer
    }

    //When the state change
    r.onreadystatechange=function(){ 
       //ReadyState 4 = Loaded     see: http://www.w3.org/TR/2006/WD-XMLHttpRequest-20060405/
       //status 200 = ok           see: http://en.wikipedia.org/wiki/List_of_HTTP_status_codes
       if(r.readyState==4 && r.status==200){
           //Replace the content with the response, Using creatDocumentFragment is more efficient 
           //at the cost of a few more lines But it  would alos allow you to append the data
           //instead of replacing it using innerHTML;
           document.getElementById(html).innerHTML = r.responseText;
        }
    }

    //Opening the connection and sending the request.
    r.open("GET",file,true); 
    r.send();
}

Upvotes: 0

Andrew
Andrew

Reputation: 7778

Well, you need to use the javascript / ajax.

Example: on your submit link (a href for exaple), add call-in-to js function submitMe and pass on whatever variables you need

function submitMe() {
    jQuery(function($) {    
        $.ajax( {           
            url : "some_php_page.php?action=getsession",
            type : "GET",
            success : function(data) {
                alert ("works!"); //or use data string to show something else
                }
            });
        });
    }

IF you want to change some content dynamically, it is easy- you just need to create tags, and assign ID to them : <div id="Dynamic"> </div>

Then you load ANYTHING between those two tags using 

document.getElementById("Dynamic").innerHTML = "<b>BOOM!</b>";

Meaning that you calling area between two tags and loading something into them. The same way you GET data from that place: 

alert(document.getElementById("Dynamic").innerHTML);

Please read this: http://www.tizag.com/javascriptT/javascript-getelementbyid.php

In addition, play and experiment with DOM elements and learn how they interact. It is not hard, just takes some time to grasp all concepts.

Upvotes: 7

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