CODEWITHSUNDEEP
c++
alessandro
alessandro

Reputation: 1721

C++: binary std::string to decimal

I want to convert 64 bit binary string to 64 bit integer (unsigned). Is there any library function to do that in C++ ?

Edit:

I use:

main()
{
std::string st = "010111000010010011000100010001110110011010110001010111010010010110100101011001010110010101101010" ;

uint64_t number;
number = strtoull (st.c_str (),NULL,2);
cout << number << " " ;

char ch = std::cin.get();
cout << ch ;


   return 0;
}

Upvotes: 6

Views: 40661

Answers (5)

PentiumPro200
PentiumPro200

Reputation: 631

Converts binary string to integer and binary string (up to 64 bits) to long. Uses bit-shifting so slightly more efficient than pow().

#include <iostream>
#include <stdio.h>
#include <string>

using namespace std;

string getBinaryString(int value, unsigned int length, bool reverse) {
    string output = string(length, '0');
    if (!reverse) {
        for (unsigned int i = 0; i < length; i++) {
            if ((value & (1 << i)) != 0) {
                output[i] = '1';
            }
        }
    }
    else {
        for (unsigned int i = 0; i < length; i++) {
            if ((value & (1 << (length - i - 1))) != 0) {
                output[i] = '1';
            }
        }
    }
    return output;
}

unsigned long getInteger(const string& input, size_t lsbindex, size_t msbindex) {
    unsigned long val = 0;
    unsigned int offset = 0;
    if (lsbindex > msbindex) {
        size_t length = lsbindex - msbindex;
        for (size_t i = msbindex; i <= lsbindex; i++, offset++) {
            if (input[i] == '1') {
                val |= (1 << (length - offset));
            }
        }
    }
    else { //lsbindex < msbindex
        for (size_t i = lsbindex; i <= msbindex; i++, offset++) {
            if (input[i] == '1') {
                val |= (1 << offset);
            }
        }
    }
    return val;
}

int main() {
    int value = 23;
    cout << value << ": " << getBinaryString(value, 5, false) << endl;
    string str = "01011";
    cout << str << ": " << getInteger(str, 1, 3) << endl;
}

Upvotes: 0

maheshmhatre
maheshmhatre

Reputation: 11

The following code is probably the simplest way to convert binary string to its integer value. Without using biteset or boost this works for any length of binary string. 

std::string binaryString = "10101010";  
int value = 0;
int indexCounter = 0;
for(int i=binaryString.length()-1;i>=0;i--){

    if(binaryString[i]=='1'){
        value += pow(2, indexCounter);
    }
    indexCounter++;
}

Upvotes: 1

ForEveR
ForEveR

Reputation: 55887

If you have C++11 - you can use std::bitset for example.

#include <iostream>
#include <bitset>

int main()
{
    const std::string s = "0010111100011100011";
    unsigned long long value = std::bitset<64>(s).to_ullong();
    std::cout << value << std::endl;
}

or std::stoull

#include <iostream>
#include <string>

int main()
{
    const std::string s = "0010111100011100011";
    unsigned long long value = std::stoull(s, 0, 2);
    std::cout << value << std::endl;
}

Upvotes: 11

user1356386
user1356386

Reputation:

You may try this. If you don't need it to be generic, you can specify the type and do away with Number:

template <typename Number>
Number process_data( const std::string& binary )
{
    const Number * data_ptr;
    Number data;

    data_ptr = reinterpret_cast<const Number*>(binary.data());
    data = *data_ptr;

    return data;
}

Upvotes: -1

Maxim Egorushkin
Maxim Egorushkin

Reputation: 136256

You can use strtoull() function with base 2 (there is an example if you follow the link).

Upvotes: 12

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