Reputation: 6040
i'm quite new to mongodb. i manage to get a basic idea of a simple sort based only 1 parameter. what if there are more than 2 sort parameters. for instance, in a database made up of woodworking projects that have attributes totalCuttingTime
and favorited
.
Is the following a correct mongoose/mongodb function to find a list of projects that have the least
totalCuttingTime and order in according to highest
favoriteCounts to lowest.
var ProjectModel= mongoose.model('Project', schema);
exports.getMinCuttingTime = function(number, callback){
var leastCutTimeResult = ProjectModel.find().sort({totalCuttingTime: 1}).select({_id: 1}).limit(number).exec(
function(err, projects) {
callback(null, projects)
}
);
var result = leastCutTimeResult.find().sort({favoriteCount: -1}).select({_id: 1}).limit(number).exec(
function(err, projects) {
callback(null, projects)
}
);
return result;
}
Upvotes: 33
Views: 33020
Reputation: 311835
You need to put both sort
terms into one object:
exports.getMinCuttingTime = function(number, callback){
ProjectModel.find()
.sort({totalCuttingTime: 1, favoriteCount: -1})
.select({_id: 1})
.limit(number)
.exec(
function(err, projects) {
callback(null, projects)
}
);
};
It's worth noting that the ECMA-262 standard on which Node.js is based doesn't specify that an object's property order is maintained, and it's only a de facto standard to match insertion order. To eliminate any doubt, you can use an array instead:
.sort([['totalCuttingTime', 1], ['favoriteCount', -1]])
Upvotes: 80