CODEWITHSUNDEEP
antbuild-automationbuild-script
jay
jay

Reputation: 811

How to use ant replaceregex task to replace a line with file path in windows?

In my build file i have an ant target in which i have following snippet ,

 <replaceregexp replace="custom.dir=${basedir}/tasks/custom" byline="true" file="${basedir}/MyApp/configuration.properties">
        <regexp pattern="custom.dir=(.*)"/>
 </replaceregexp>

I wanted to replace the "custom.dir" property with a path in the "configuration.properties" file , however once i execute my target i get the entry for "custom.dir" property modified to

custom.dir=c:arenaplaygroundmytestapp/tasks/custom

instead of

custom.dir=c:\arena\playground\mytestapp/tasks/custom

What should i do to write the path correctly to the "configuration.properties" file with proper file separators . I am on windows and ant used is ant 1.8 .

Upvotes: 3

Views: 3740

Answers (1)

Vishal
Vishal

Reputation: 3279

When you are trying to write WINDOW_STYLE_PATH to your file, then WINDOW_FILE_SEPARATOR is recognized as escaping sequence character. So you can change the path in unix style before writing it to the file. Pathconvert will assist you to convert the path...

<pathconvert property="new" dirsep="/">
    <path location="${basedir}"/>
</pathconvert>
    <echo message="${new}"/>
 <replaceregexp replace="custom.dir=${new}/tasks/custom" byline="true" file="${basedir}/configuration.properties">
        <regexp pattern="custom.dir=(.*)"/>
 </replaceregexp>

Upvotes: 5

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