CODEWITHSUNDEEP
bashshellunix
Smithis
Smithis

Reputation: 55

2 grep in if statement

Anyone can tell me what will be the problem?i know that this is a half sec problem but pls help:) egrep "first" a.sh && egrep "second" a.sh works, a.sh contains first,second,third etc.. Thx!

 if [[ egrep "first" a.sh && egrep "second" a.sh ]]; then
 echo "success"
 fi

Upvotes: 2

Views: 4006

Answers (2)

sampson-chen
sampson-chen

Reputation: 47267

I think this may be what you are looking to do:

found_1=$(egrep "first" a.sh)
found_2=$(egrep "second" a.sh)

if [[ -n "$found_1" ]] && [[ -n "$found_2" ]]; then
    echo "success"
fi

Upvotes: 1

Ignacio Vazquez-Abrams
Ignacio Vazquez-Abrams

Reputation: 798686

Your problem is that you're using the [[ command. Use just the greps.

if egrep ... && egrep ... ; then

Upvotes: 8

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