CODEWITHSUNDEEP
javaandroidfile
John Roberts
John Roberts

Reputation: 5986

Getting file path for local Android project files

I want to programmatically access a specific file which will be included in my project folder. Is there a way to do this? If so, where in my project folder do I put the file, and what is some simple code to get its file path?

private void saveFileToDrive() {
        Thread t = new Thread(new Runnable() {
            @Override
            public void run() {
                try {
                    java.io.File spreadsheet = new java.io.File("Untitled spreadsheet.xlsx");
                    String filePath = spreadsheet.getAbsolutePath();
                    System.out.println("file path is"+filePath);

                    URL fileURL = getClass().getClassLoader().getResource("Untitled spreadsheet.xlsx");
                    String filePath2 = fileURL.getPath();
                    System.out.println("file path2 is"+filePath2);

                    java.io.File fileContent = new java.io.File(filePath);
                    FileContent mediaContent = new FileContent("application/vnd.ms-excel", fileContent);

                    File body = new File();
                    body.setTitle(fileContent.getName());
                    body.setMimeType("application/vnd.ms-excel");


                    File file = service.files().insert(body, mediaContent).setConvert(true).execute();

                    if (file != null) {
                        showToast("File uploaded: " + file.getTitle());
                    }
                    else
                             ;
                } catch (UserRecoverableAuthIOException e) {

                    startActivityForResult(e.getIntent(), REQUEST_AUTHORIZATION);
                } catch (IOException e) {

                    e.printStackTrace();
                }
            }
        });
        t.start();
    }

Upvotes: 7

Views: 42580

Answers (3)

John Bentley
John Bentley

Reputation: 1834

So you want to access a file internal to your app; and you want to do so directly, rather, that is, from an Android Context (and then with a [android.|<package_name>.]R.<resource_type>.<resource_name>).

You have two choices as to location: the res/raw folder or assets/ folder (outside of the res parent).

To choose between the two note from https://developer.android.com/guide/topics/resources/providing-resources.html

Arbitrary files to save in their raw form. To open these resources with a raw InputStream, call Resources.openRawResource() with the resource ID, which is R.raw.filename.

However, if you need access to original file names and file hierarchy, you might consider saving some resources in the assets/ directory (instead of res/raw/). Files in assets/ aren't given a resource ID, so you can read them only using AssetManager.

To access a file in res/raw/ directly rather, that is, from an Android Context (and then with a [android.|<package_name>.]R.<resource_type>.<resource_name>) you can do something like this:

File file = new File("app/src/main/res/raw/country_data_from_world_bank.xml");
BufferedReader bufferedReader = new BufferedReader(new FileReader(file));

Upvotes: 0

Yogendra Singh
Yogendra Singh

Reputation: 34397

Put the file in root folder of your project. Then get the File URL, Path and other details as:

   File file = new File("test.txt");
   String filePath = file.getAbsolutePath();

EDIT: Alternate way (if the file is in your classpath e.g. put the file in "src" folder, and make sure its moved in "bin" or "classes" folder after compilation):

  URL fileURL = getClass().getClassLoader().getResource(fileName);
  String fileName = fileURL.getFile();
  String filePath = fileURL.getPath();

Upvotes: 5

Code-Apprentice
Code-Apprentice

Reputation: 83587

This depends a lot on what type of file you want to access. You can put the file in either assets or an appropriate subdirectory of res (see Difference between /res and /assets directories).

Upvotes: 0

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