CODEWITHSUNDEEP
pythonpython-2.7file-handling
user19911303
user19911303

Reputation: 449

error "invalid filename" if i use letters a to f in file name

i'm using pyton 2.7. I have written a script , when it is executed, it will call and run some other file with the name abc.py. but i'm getting error 

IOError: [Errno 22] invalid mode ('r') or filename: 'F:\x07bc.c'

it is working fine if i change the file name. it shows error only if i use letters from a to f as the first letter of file name Please help. Thank you

Upvotes: 0

Views: 3989

Answers (3)

eumiro
eumiro

Reputation: 212835

Try this:

open(r'F:\abc.c')

i.e. add r before quotes.

UPDATE Sorry, I misinterpreted the code (although my solution is correct). @DavidHeffernan is right, the \a is read as the ASCII bell.

Upvotes: 1

David Heffernan
David Heffernan

Reputation: 612874

Consider the Python string '\a'. As described in the documentation, the back slash character is interpreted as an escape character. So '\a' is in fact the ASCII Bell character, character number 7.

Your filename is 'F:\abc.c' and the \a in there is interpreted as ASCII Bell. You can see this clearly in the interpretor:

>>> 'F:\abc.c'
'F:\x07bc.c'
>>> print 'F:\abc.c'
F:bc.c

When you print that string note that the \a does not appear. That's because it has been turned into a Bell control character which is invisible.

To include a backslash you can use the correct escape sequence \\. Put it all together and your filename should be: 'F:\\abc.c'. As an alternative, you can prefix the string with r to make it a raw string. This is also detailed in the documentation.

>>> 'F:\\abc.c'
'F:\\abc.c'
>>> print 'F:\\abc.c'
F:\abc.c
>>> r'F:\abc.c'
'F:\\abc.c'
>>> print r'F:\abc.c'
F:\abc.c

Upvotes: 5

Fabian
Fabian

Reputation: 4348

Escape the \ with another backslash, like this:

print 'F:\\x07bc.c'

Upvotes: 1

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