CODEWITHSUNDEEP
antlrantlr4
Guy
Guy

Reputation: 43

ANTLR4 Beta 3 Very simple grammar not working

Here is a very simple grammar:

grammar test;

DIGIT : [0-9] ;
WS : [ \r\n\t]+ -> skip ;
value : DIGIT+ ;

Using antlr v4.0b3 under OSX and JAVA version 1.6

Compiling the grammar with the following commands:

antlr4 test.g4
javac *.java

I then used grun to test the grammar:

grun test value -tokens

And here is the result:

grun test value -tokens
12
[eof]
[@0,0:0='1',<1>,1:0]
[@1,1:1='2',<1>,1:1]
[@2,3:2='<EOF>',<-1>,2:0]

My question is: why do I get two tokens ('1' and '2') instead of one ('12')?

Thanks a lot for those who can help me!!

Cheers!

Guy

Upvotes: 3

Views: 338

Answers (1)

Terence Parr
Terence Parr

Reputation: 5962

You have asked DIGIT to match a single digit at a time, which are then passed to the parser rule: value. I think what you want is really

value : INT ;
INT : [0-9]+ ;

:)

Terence

Upvotes: 4

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