CODEWITHSUNDEEP
javascriptjquery
user1534664
user1534664

Reputation: 3418

Remove last line from string

How do I remove the last line "\n" from a string, if I dont know how big the string will be?

var tempHTML = content.document.body.innerHTML;
var HTMLWithoutLastLine = RemoveLastLine(tempHTML);

function RemoveLastLine(tempHTML)
{
   // code
}

Upvotes: 21

Views: 27041

Answers (6)

Benbb96
Benbb96

Reputation: 2263

I use trimEnd to remove last line of a string:

const text = `test
multiple
lines
`

const lines = text.trimEnd().strip('\n')

Upvotes: 0

Dan Froberg
Dan Froberg

Reputation: 208

Make the string to an array and pop away the last line.

The value from the pop is not used, so it go to the void.

function RemoveLastLine(x) {
    x = x.split('\n');
    x.pop();
    return x.join('\n')
}

Make it back to a string with Array.join()

Upvotes: 0

Marco Roy
Marco Roy

Reputation: 5243

A regex will do it. Here's the simplest one:

string.replace(/\n.*$/, '')

See regex101 for how it works

\n matches the last line break in the string

.* matches any character, between zero and unlimited times (except for line terminators). So this works whether or not there is content on the last line

$ to match the end of the string

Upvotes: 4

ivoputzer
ivoputzer

Reputation: 6469

In your specific case the function could indeed look like:

function(s){
  return i = s.lastIndexOf("\n")
    , s.substring(0, i)
}

Though probably you dont want to have spaces at the end either; in this case a simple replace might work well:

s.replace(/s+$/, '')

Keep in mind however that new versions of Javascript (ES6+) offer shorthand ways of doing this with built-in prototype functions (trim, trimLeft, trimRight)

s.trimRight()

Cheers!

Upvotes: 1

rekire
rekire

Reputation: 47945

Try:

if(x.lastIndexOf("\n")>0) {
    return x.substring(0, x.lastIndexOf("\n"));
} else {
    return x;
}

Upvotes: 30

Julien Royer
Julien Royer

Reputation: 1429

You can use a regular expression (to be tuned depending on what you mean by "last line"):

return x.replace(/\r?\n?[^\r\n]*$/, "");

Upvotes: 10

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