CODEWITHSUNDEEP
c++
user1868095
user1868095

Reputation: 23

no suitable conversion from "std::string" to "char" exists

I'm working on a project for school and I am running into a bit of a problem (error is in the title).

Here is the line of code that runs into the error:

kruskalS[n].nodeList[m].push_back(tempFirstCity);

kruskalS is a struct and nodeList is a vector of type string within the struct and I'm trying to insert tempFirstCity (also a string) into that array.

I could easily be making a basic mistake since I haven't done any programming since April. Any kind of help would be appreciated and I'm willing to post a bit more information from the program if needed.

Upvotes: 2

Views: 18000

Answers (4)

acraig5075
acraig5075

Reputation: 10756

You say nodeList is an array of type string. i.e. std::string nodeList[x] where x is a constant.

Then assigning a new element to that array where m < x is as follows:

kruskalS[n].nodeList[m] = tempFirstCity;

Based on comments:

For appending to end of vector you don't need the index m:

kruskalS[n].nodeList.push_back(tempFirstCity);

For inserting at index m:

vector<string>::iterator itr = nodeList.begin();
for (int i = 0; i < m; i++)
  itr++;
nodeList.insert(itr, tempFirstCity);

Upvotes: 0

aschepler
aschepler

Reputation: 72271

A std::string is (sort of) a container of chars. A push_back function is used to add one element to the end of a container. So when you call kruskalS[n].nodeList[m].push_back(tempFirstCity);, you say you are trying to add one element to the end of the string called kruskalS[n].nodeList[m]. So the compiler expects that one element to be a char.

If you know that tempFirstCity is not empty and you want to add the first char from tempFirstCity to the end of kruskalS[n].nodeList[m] (including the case where you know tempFirstCity.size() == 1), you can do

kruskalS[n].nodeList[m].push_back(tempFirstCity[0]);

If you want to add the entire string after any current contents, you can do

kruskalS[n].nodeList[m] += tempFirstCity;

If you expect there are no current contents and/or you want to just replace anything already there with the tempFirstCity string, you can do

kruskalS[n].nodeList[m] = tempFirstCity;

Upvotes: 5

bhuang3
bhuang3

Reputation: 3633

In C++, you can use string::c_str() to convert a string to C programming char array..

Upvotes: -2

Alok Save
Alok Save

Reputation: 206498

You can use: 

std::string::c_str()

It returns a const char *.

Upvotes: 5

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