CODEWITHSUNDEEP
pythonregexpython-3.x
user1261817
user1261817

Reputation: 1593

How to split string before number

I have a string 1 blahblahblah 2 sdsdsdsdsd 3 uuuuuu 4 eeee 5 abcdef I would like to output

1 blahblahblah
2 sdsdsdsdsd
3 uuuuuu
4 eeee
5 abcdef

I have tried to add \n before every number by using re.split but it didn't work

re.split(' (?=[1-9]:)', line)

Upvotes: 1

Views: 4215

Answers (4)

ovgolovin
ovgolovin

Reputation: 13410

Without using re:

>>> s = '1 blahblahblah 2 sdsdsdsdsd 3 uuuuuu 4 eeee 5 abcdef'
>>> for i,word in zip(*[iter(s.split())]*2):
    i = int(i)
    print('{i} {word}'.format(**locals()))

Output:

1 blahblahblah
2 sdsdsdsdsd
3 uuuuuu
4 eeee
5 abcdef

Upvotes: 0

unutbu
unutbu

Reputation: 879291

Here is another way to do the substitution without inserting a newline before the first number:

In [62]: print(re.sub(r'\s(\d)', r'\n\1', line))
1 blahblahblah
2 sdsdsdsdsd
3 uuuuuu
4 eeee
5 abcdef

Upvotes: 1

Martijn Pieters
Martijn Pieters

Reputation: 1121486

The following works just fine:

re.sub(r'(\d+)', '\n\\1', input)

Demo:

>>> print(re.sub(r'(\d+)', r'\n\1', input))

1 blahblahblah 
2 sdsdsdsdsd 
3 uuuuuu 
4 eeee 
5 abcdef

The expression (\d+) matches 1 or more digits, and I replace that with a newline followed by the matched digits (via the capturing group).

Upvotes: 5

phihag
phihag

Reputation: 287775

Use a group:

>>> s = '1 blahblahblah 2 sdsdsdsdsd 3 uuuuuu 4 eeee 5 abcdef'
>>> import re
>>> print(re.sub(r'([0-9]+)', r'\n\1', s))

1 blahblahblah 
2 sdsdsdsdsd 
3 uuuuuu 
4 eeee 
5 abcdef

To remove the first newline, you can add a negative lookbehind:

>>> print(re.sub(r'(?<!^)([0-9]+)', r'\n\1', s))
1 blahblahblah 
2 sdsdsdsdsd 
3 uuuuuu 
4 eeee 
5 abcdef

Upvotes: 1

Related Questions