CODEWITHSUNDEEP
jqueryattr
EasyBB
EasyBB

Reputation: 6554

variable to use with finding the title of an element

$(document).ready(function() { 
var $postBG = $('.post .poster-profile img'); 
$postBG.find("[title='male']")
    .closest('tr')
      .addClass('male')
        .children('td')
         .removeClass('row1 row2');
$postBG.find("[title='female']")
   .closest('tr')
     .addClass('female')
      .children('td')
       .removeClass('row1 row2');
 });

Just trying to find if the img title is female or male, and then do the following codes above. I tried

$postBG.attr("male")

that did not work though any help please

Upvotes: 0

Views: 50

Answers (1)

Ram
Ram

Reputation: 144689

find finds the elements within the context of the selected element, you can use filter method:

var $postBG = $('.post .poster-profile img'); 
$postBG.filter('[title="male"]').foo()

or attribute selector instead:

var $postBG = $('.post .poster-profile img[title="male"]');

Upvotes: 1

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