CODEWITHSUNDEEP
c++templates
user1190294
user1190294

Reputation:

Template function specialisation

How to make a specialisation for a template function with returning value template?

I tried this:

myfunc.h:

#pragma once

template< >
int MyFunc<int>(){
   return 10;
}

main.cpp:

#include "myfunc.h"

int main()
{
    int a;
    a = MyFunc<int>();
    return 0;
}

but i have error: expected initializer before '<' token

Upvotes: 0

Views: 208

Answers (3)

dmayola
dmayola

Reputation: 512

I don't know what are you trying to do but maybe this helps you:

template<typename T>
int MyFunc(){
   return 0;
}

template<>
int MyFunc<int>(){
   return 10;
}

template<>
int MyFunc<char>(){
   return 100;
}

using namespace std;

int main()
{
    cout << MyFunc<int>() << endl << MyFunc<char>() << endl;
    system("pause");

    return 0;
}

Upvotes: 0

Puppy
Puppy

Reputation: 146930

You did not declare or define a primary template of which this is a specialization.

Upvotes: 2

pmr
pmr

Reputation: 59811

You are missing the primary template before you declare your specialization.

template<typename> int func() { return 42; }

template<> int func<int>() { return 23; }

Please be aware of the problems of function specializations.

Upvotes: 4

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