Reputation: 9509

How do I read and edit a .txt file in C#?

For example, I have a txt file that reads:

12 345 45
2342 234 45 2 2 45345
234 546 34 3 45 65 765
12 23 434 34 56 76 5

I want to insert a comma between all the numbers, add a left brace to the begining of each line and a right brace to the end of each line. So after the editing it should read:

{12, 345, 45}
{2342, 234, 45, 2, 2, 45345}
{234, 546, 34, 3, 45, 65, 765}
{12, 23, 434, 34, 56, 76, 5}

How do I do it?

Upvotes: 9

Answers (9)

George Powell

Reputation: 9509

In the end I used a second file rather than editing the first:

TextReader reader = new StreamReader("triangle.txt");
TextWriter writer = new StreamWriter("triangle2.txt");
for (; ; )
{
    string s = reader.ReadLine();
    if (s == null)
       break;
    s = s.Replace(" ", ", ");
    s = "{" + s + "},";
    writer.WriteLine(s);
}

Upvotes: 1

jb.

Reputation: 10351

edit to add how to modify sLine. (not tested, but I'm pretty sure it'll work just fine)

    StreamReader sr = new StreamReader("path/to/file.txt");
    StreamWriter sw = new StreamWriter("path/to/outfile.txt");
    string sLine = sr.ReadLine();
    for (; sLine != null; sLine = sr.ReadLine() )
    {
        sLine = "{" + sLine.Replace(" ", ", ") + "}";
        sw.WriteLine(sLine);
    }

Upvotes: 3

Donut

Reputation: 112895

You'll need to use the FileStream class to open the file, the StreamReader class to read from the file, and the StreamWriter class to write back to the file.

You can create a FileStream like this:

FileStream file = new FileStream("FileName", FileMode.Open, FileAccess.ReadWrite);

Then wrap the FileStream in a StreamReader:

StreamReader reader = new StreamReader(file);

Then, read in each line and do your string processing (adding commas and brackets):

while(reader.EndOfFile)
{
   string currentLine = reader.ReadLine();
   // do your string processing here and save the result somewhere
}

Lastly, wrap the FileStream in a StreamWriter and write your modified strings back to the file:

StreamWriter writer = new StreamWriter(file);

// Write your content here
writer.Write("my content");

Don't forget to close your streams after working with them.

reader.Close();
writer.Close();
file.Close();

Upvotes: 3

aanund

Reputation: 1492

Added some LINQ for fun and profit (room for optimization ;) ):

System.IO.File.WriteAllLines(
    "outfilename.txt",
    System.IO.File.ReadAllLines("infilename.txt").Select(line =>
        "{" +
        string.Join(", ",
            line.Split(new string[] { " " }, StringSplitOptions.RemoveEmptyEntries)
        ) + "}"
    ).ToArray()
);

Upvotes: 20

Mehmet Aras

Reputation: 5374

string [] lines = File.ReadAllLines("input.txt");
var processed = lines.Select(line => string.Format("{{{0}}}", line.Replace(" ", ", ")));
File.WriteAllLines("output.txt",processed.ToArray());

Upvotes: 3

cw22

Reputation: 188

you should work on the logic first instead of directly asking people to provide that for you. as for reading/writing a file, here you go:

//write      
FileStream fs = new FileStream("file_name", FileMode.Create);
StreamWriter w = new StreamWriter(fs, Encoding.UTF8);
w.WriteLine("text_to_write");
w.Flush();
w.Close();
fs.Close();

//read
fs = new FileStream("file_name", FileMode.Open);
StreamReader r = new StreamReader(fs, Encoding.UTF8);
Console.WriteLine(r.ReadLine());
r.Close();
fs.Close();

Upvotes: 4

Mark Redman

Reputation: 24535

Something like this: (NOT TESTED)

string filename = @"c:\yourfilename.txt";
StringBuilder result = new StringBuilder();

            if (System.IO.File.Exists(filename))
            {
                using (StreamReader streamReader = new StreamReader(filename))
                {
                    String line;
                    while ((line = streamReader.ReadLine()) != null)
                    {
                        string newLine = String.Concat("{", line, "}", Environment.NewLine);
                        newLine = newLine.Replace(" ", ", ");
                        result.Append(newLine);
                    }
                }
            }

using (FileStream fileStream = new FileStream(filename , fileMode, fileAccess))
            {
                StreamWriter streamWriter = new StreamWriter(fileStream);
                streamWriter.Write(result);
                streamWriter.Close();
                fileStream.Close();
            }

Upvotes: 13