CODEWITHSUNDEEP
regexshell
Pranav
Pranav

Reputation: 2172

Shell program to extract data from log files

I will be writing a shell script to go through the log file generated by my application , I need to separate out only function names and minimum info about the call from the logs generated.

Log file format will be - 0.0003 636488 +440 -> include_once(/var/www/public/const.php) /var/www/public/ajax_shop.php:2

Now, out of such line I want to extract that - "include_once" was called at line "2" from the file "ajax_shop.php"

how should I use regular expression in shell script for this situation ?

Upvotes: 2

Views: 1360

Answers (1)

Guru
Guru

Reputation: 17054

One way using sed:

sed 's/.*-> \([^(]*\).*:\(.*\)/\1 was called at line \2/' logfile
include_once was called at line 2.

\([^(]*\) => This matches till a closing bracket is encountered. [^(]* => Means a series of characters which is not a '('.

Using awk:

$ awk -F"[>(:]" '{print $2 " was called at line " $NF}' logfile
 include_once was called at line 2.

awk uses multiple delimiters >,( and :. Using this, it becomes simple just to print the 2nd field and the last field.

Upvotes: 3

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